Question 1131406
<br>
{{{(64/729)^x = 243/32}}}<br>
Observe that 64, 729, 243, and 32 are all powers of 2 or 3....<br>
{{{((2/3)^6)^x = (3/2)^5}}}
{{{(2/3)^(6x) = (2/3)^(-5)}}}<br>
The bases are the same, so the exponents are equal:<br>
{{{6x = -5}}}<br>
{{{x = -5/6}}}