Question 102809
(x-1)^2 = 7 ... taking square root gives x-1=+-sqrt(7) ... {{{x=1 +- sqrt(7)}}}


4x^2 - 8x + 3 = 5 ... 4x^2-8x-2=0 ... 2x^2-4x-1=0 ... {{{x=(4 +- sqrt(16-4(2)(-1)))/(2*2)}}} ... {{{x=(2 +- sqrt(6))/2}}}