Question 1131357
2. Sum of interior angles of regular polygon = 2340
The sum of the interior angles of an n-sided polygon = 180(n-2). 
Two examples are n = 3, equilateral triangle, S = 180 deg and n = 4, square, S = 360
2340 = 180(n-2)
n = 2340/180 + 2 = 15
The measure of one interior angle = 2340/15 = 156
The measure of one exterior angle = 360 - 156 = 204


3. If the exterior angle = 20, this implies an interior angle of 340 degrees.
Interior angles of polygons must be less than 180 degrees, so the polygon does not exist.

5.  Heptagon has more sides and thus the larger interior angle
Heptagon: 180(7-2) = 900 -> Interior angle = 900/7 = 128.57
Hexagon: 180(6-2) = 720 -> Interior angle = 720/6 = 120
Greater by 8.57 deg

7. Let x = the smallest angle.  180(n-2) = 720 = x + x+1 + x+2 + x+3 + x+4 + x+5
180(n-2) = 6x + 15 = 720
x = 705/6 = 117.5