Question 1131361
{{{f(x) = x^2 -8x + 2}}}

{{{y =(x^2 -8x) + 2}}}

{{{y =(x^2 -8x+b^2) -b^2+ 2}}}.......{{{b=8/2=4}}}

{{{y =(x^2 -8x+4^2) -4^2+ 2}}}

{{{y =(x -4)^2 -16+ 2}}}

{{{y =(x -4)^2 -14}}}

=> {{{h=4}}} and {{{k=-14}}}

vertex ({{{x}}}, {{{y}}}) =({{{4}}}, {{{-14}}})

axis of symmetry 

{{{x =4}}}


 {{{drawing ( 600, 600, -15, 15, -15, 15, 
circle(4,-14,.12), locate(4,-14,V(4,-14)), line(4,-15,4,15),
graph( 600, 600, -15, 15, -15, 15, (x -4)^2 -14)) }}}