Question 1131311
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x^2-7xy+6y=0
x^2+xy=42
Solve the system
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Elimination of xy gives  {{{y=7/(x-1)}}}.


Elimination of x^2 gives  {{{4x^2+3y=147}}}.


Substitution for y and then gives  {{{4x^2+21/(x-1)=147}}}.


(If no mistakes were made,...) which should simplify to
{{{4x^3-4x^2-147x+168=0}}}
Go from there.
(Not a finished solution)