<PRE><B>Question 102863</B>
The sum of two numbers is 15. Three times one of the numbers is 11 less than five times the other. Find the numbers.
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x+y = 15
3x+11 = 5y
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Rearrange:
1x +1y =  15
3x -5y = -11
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Multiply thru 1st by 3 to get:
3x+3y = 45
3x-5y = -11
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Subtract 2nd from 1st to get:
8y = 56
y = 7 (one of the numbers)
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Substitute into x+y=15 to solve for x:
x+7=15
x = 8 (the other number)
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Cheers,
Stan H.</PRE>