Question 1131221
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There are 6 ways to choose the first name.  Then, for each of those 6 ways, there are 5 ways to choose the second name, for a total of 30 ways to choose the first two names, then times 4, then times 3...  But this is just the formula for the number of PERMUTATIONS of 6 things, namely 6 factorial.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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