Question 1131215
given:

{{{f(x)=2x^2-3 }}}and {{{g(x)=4x}}}

to find: 

(f o g)(1) or {{{f(g(1))}}}


first find {{{f(g(x))}}}


{{{f(g(x))=f(4x)}}}

{{{f(g(x))=2(4x)^2-3}}}

{{{f(g(x))=2(16x^2)-3}}}

{{{f(g(x))=32x^2-3}}}


then


{{{f(g(1))=32*1^2-3}}}

{{{f(g(1))=32-3}}}

{{{f(g(1))=29}}}