Question 1131209
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Solve the system
2x^2-4xy+16y^2=2
3x+4y=3
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{{{4y=3-3x}}}
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{{{2x^2-4xy+16y^2=2}}}
{{{2x^2-4yx+16y^2=2}}}
{{{2x^2-(3x-3x^2)+9-18x+9x^2=2}}}
{{{2x^2-3x+3x^2+9-18x+9x^2=2}}}
{{{14x^2-21x+7=0}}}
{{{2x^2-3x+1=0}}}
{{{(2x-1)(x-1)=0}}}

{{{system(x=1/2,OR,x=1)}}}
and you can find the y values corresponding to each of these x values.