Question 1131140
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<pre>
From the condition, you have this system of 2 equations in 2 unknowns


     x = y + 1000,        (1)   ("The investor puts $1000 more in the first account than in the stock fund")

0.12*x + 0.08*y = 890     (2)   (at the end of the year finds the total interest from the two investments was $890.")


where x is the investment at 12% and y is the investment at 8%.


To solve the system, substitute expression (1) into equation (2). You will get


    0.12(y+1000) + 0.08y = 890

    0.12y + 120 + 0.08y = 890

    0.2y = 890 - 120 = 770

    y = {{{670/0.2}}} = 3850.


<U>Answer</U>.  $3850 invested at 8% and $1000 dollars more, i.e. 4850 dollars invested at 12%.


<U>CHECK</U>.   0.08*3850 + 0.12*4850 = 890  dollars.     ! Correct !
</pre>

Solved.


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It is a standard and typical problem on investments.


If you need more details,  &nbsp;or if you want to see other similar problems solved by different methods, &nbsp;look into the lesson 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.