Question 1131098
{{{(k^3-1)/(k-1)}}}

={{{((k - 1)(k^2 + k + 1) )/(k - 1)}}}


={{{(cross((k - 1))(k^2 + k + 1) )/cross((k - 1))}}}


={{{k^2 + k + 1}}}



For {{{k<>1}}}, we have {{{(k^3-1)/(k-1)=k^2+k+1}}}. Either there is a typo somewhere, or the calculation is not quoted correctly.