Question 1131085
{{{x^2-4y-4x=0}}}

{{{x^2-4x=4y}}}

{{{y=(1/4)x^2-x}}}

{{{y=x(x/4-1)}}}


Obviously the two x-axis intercepts are 0 and 4.  The minimum value occurs at x=2.    You can plug in other values for x and find the y of each and plot these points.