Question 1131054

({{{6}}},{{{8}}}), ({{{r}}}, {{{-2}}}),{{{m=1 }}}

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{1=(-2-8)/(r-6)}}}
{{{(r-6)=(-2-8)}}}
{{{r-6=-10}}}
{{{r=-10+6}}}
{{{r=-4}}}