Question 1131050
{{{x<y}}}


This is the system according to description.  This is literally what the description says:
{{{system(x+y=40,y/x=x/2+1)}}}


substituting {{{y=40-x}}} into the rational equation,
{{{(40-x)/x=x/2+1}}}

{{{2x(40-x)/x=2x(x/2)+2x*1}}}

{{{80-2x=x^2+2x}}}, simplifying to ,...


{{{highlight_green(x^2+4x-80=0)}}}


Use the general formula solution for quadratic equation to find x and each corresponding y.  You do that further arithmetic.
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{{{x=-2-2*sqrt(21)}}} and {{{y=42+2*sqrt(21)}}}

OR

{{{x=-2+2*sqrt(21)}}} and  {{{y=42-2*sqrt(21)}}}