Question 1131011
.


Let me show to you &nbsp;<U>much &nbsp;MORE &nbsp;REASONABLE &nbsp;way</U> &nbsp;to solve it by the Substitution method.


<pre>
6x + 7y = -9      (1)
2x + 5y =  5      (2)


The term " 6x " in equation (1) is three times the term "2x" in the in equation (2).

Therefore, it is TOTALLY ENOUGH to express 2x from equation (2) as  2x = 5 - 5y  and then substitute it into 
equation (1), replacing " 6x " there  as 3*(2x). You will get then


    3*(5-5y) + 7y = -9

    15 - 15y + 7y = -9

    -8y = -9 - 15 = -24

    y  = {{{-24/(-8)}}} = 3.


Now substitute this value  y= 3 into equation (2) to get

    2*x + 5*3 = 5

    2x + 15 = 5

    2x = 5 - 15 = -10

    x = {{{-10/2}}} = -5.


<U>Answer</U>.  The solution is  x= -5,  y= 3.


Check the solution on your own by substituting the found values into the given equations.
</pre>

Solved.


---------------


By doing in this way, you avoid working with fractions and denominators.


Less computing - less chance to make an error.