Question 1131001


{{{y=5x-7}}}.......eq.1

{{{ -3x-2y=-12}}}.......eq.2
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{{{ -3x-2y=-12}}}.......eq.2....substitute {{{y}}} from eq.1

{{{ -3x-2(5x-7)=-12}}}.......solve for {{{x}}}

{{{ -3x-10x+14=-12}}}

{{{ -13x+14=-12}}}

{{{ 12+14=13x}}}

{{{ 26=13x}}}

{{{ x=26/13}}}

{{{ x=2}}}

go to

{{{y=5x-7}}}.......eq.1 ...substitute {{{x=2}}}

{{{y=5*2-7}}}

{{{y=10-7}}}

{{{y=3}}}



{{{ graph( 600, 600, -10, 10, -10, 10, 5x-7, -3x/2+6) }}}