Question 1130940
Put in the parentheses if you really have  (3a^3-24)/(3a^2+6a+12).


{{{(3a^3-24)/(3a^2+6a+12)}}}


{{{(a^3-8)/(a^2+2a+4)}}}

and you can either derive or look up how to factorize your numerator.

{{{((a-2)(a^2+2a+4))/(a^2+2a+4)}}}


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