Question 1130876

 Given that the perimeter of the rectangle is:


{{{P= 120cm}}}


  length and breadth as indicated:

{{{3x-y}}}
{{{2x-3}}}
{{{2x+y}}}
{{{2x-3}}}



{{{3x-y+2x-3+2x+y+2x-3= 120}}}

{{{3x-cross(y)+2x-3+2x+cross(y)+2x-3= 120}}}

{{{3x+2x+2x+2x-3-3= 120}}}

{{{9x-6= 120}}}

{{{9x= 120+6}}}

{{{9x= 126}}}

{{{x= 126/9}}}

{{{x= 14}}



=>
{{{3x-y}}}={{{3*14-y}}}={{{42-y}}}
{{{2x-3}}}={{{2*14-3}}}={{{25}}}
{{{2x+y}}}={{{2*14+y}}}={{{28+y}}}
{{{2x-3}}}={{{25}}}


=>{{{42-y=28+y}}}
=>{{{42-28=y+y}}}
=>{{{14=2y}}}
=>{{{y=7}}}


then {{{42-y}}}->{{{42-7}}}->{{{35}}}
and {{{28+y}}}->{{{28+7}}}->{{{35}}}

so the length is {{{35}}} and the width is {{{25}}}


the area of the rectangle will be:

{{{A=35*25=875cm^2}}}