Question 1130719
10^4logx - 7(10^2logx) + 10 = 0
<pre>It's safe to say that this is: {{{matrix(1,3, 10^(4 log (x)) - 7(10^(2 log (x))) + 10, "=", 0)}}}
If it is, then IGNORE GREENSTAMP'S attempt. He doesn't have much sense and just loves to criticize. 
Plus, he thinks he knows everything. 
Let {{{matrix(1,3, a, "=", 10^(2 log (x)))}}}
Then {{{matrix(1,7, a^2, "=", 10^(2(2 log (x))), "======>", a^2, "=", 10^(4 log (x))))}}}
Then {{{matrix(1,7, 10^(4 log (x)) - 7(10^(2 log (x))) + 10, "=", 0, "becomes:", a^2 - 7a + 10, "=", 0)}}}
(a - 5)(a - 2) = 0
a - 5 = 0           OR                a - 2 = 0
a = 5               OR                a = 2
{{{system(matrix(1,3, 10^(2 log (x)), "=", 5), OR, matrix(1,3, 10^(2 log (x)), "=", 2))}}} ----- Replacing a with {{{10^(2 log (x)))}}}
CONVERTING EACH from EXPONENTIAL form above to LOGARITHMIC form gives the following results:
{{{system(matrix(1,17, log ((5)), "=", 2 log (x), "======>", log ((5)), "=", log ((x))^2, "======>", 5, "=", x^2, "======>", x, "=", " "+- sqrt(5), "======>", highlight(highlight_green(highlight(matrix(1,3, x, "=", sqrt(5)))))), OR, matrix(1,17, log ((2)), "=", 2 log (x), "======>", log ((2)), "=", log ((x))^2, "======>", 2, "=", x^2, "======>", x, "=", " "+- sqrt(2), "======>", highlight(highlight_green(highlight(matrix(1,3, x, "=", sqrt(2)))))))}}}