Question 1130762
{{{x^2+2x-4=0}}}
Factorable easily?  No.


{{{x=(-2+- sqrt(2^2-4*(-4)))/2}}}

{{{x=(-2+- sqrt(20))/2}}}

{{{x=(-2+- 2*sqrt(5))/2}}}

{{{highlight(x=-1+- sqrt(5))}}}