Question 1130626


{{{y + 2 = -3(x - 1)}}}

{{{y + 2 = -3x + 3}}}

{{{y  = -3x + 3-2}}}

{{{y  = -3x + 1}}}


find  two points to graph it

{{{x}}}|{{{y}}}

{{{0}}}|{{{1}}}->{{{y  = -3*0 + 1}}}->{{{y  = 1}}}

{{{1/3}}}|{{{0}}}->{{{0 = -3x + 1}}}->{{{3x = 1}}}->{{{x = 1/3}}}

{{{drawing( 600, 600, -10, 10, -10, 10,
circle(0,1,.12), locate(0,1,p(0,1)),circle(1/3,0,.12), locate(1/3,0,p(1/3,0)),
 graph( 600, 600, -10, 10, -10, 10, -3x + 1)) }}}