Question 1130540
he fuel efficiency for a certain midsize car is given by
E(v) = −0.014v^2 + 1.176v + 3.2
where E(v) is the fuel efficiency in miles per gallon for a car traveling v miles per hour.
(a) What speed will yield the maximum fuel efficiency? Round to the nearest mile per hour. mph
E(v) = .014v^2 + 1.176v + 3.2
Max efficiency occurs on the axis of symmetry using the formula x =-b/(2a)
Where: a= -.014; b= 1.176
v = {{{(-1.176)/(2*-.014)}}}
v = {{{(-1.176)/(-.028)}}}
v = +42 mph gives max efficiency
:
(b) What is the maximum fuel efficiency for this car? Round to the nearest mile per gallon. mpg 
v = 42
E(v) = .014(42^2) + 1.176(42) + 3.2
E(v) = .014(1764) + 49.4 + 3.2
E(v) = -24.7 + 49.4 + 3.2
E(v) = 27.9 ~ 28 mpg