Question 1130523
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Reading your post, I assume that you are a novice in this area.

So, I will show you the simplest method and the simplest way students usually learn this subject.


 x - 5y = 20     (1)
2x +  y = 14     (2)


From equation (1), express  x = 20 + 5y.   Then substitute this expression into equation (2), replacing x.

You will get a single equation for "y"


2*(20+5y) + y = 14


40 + 10y + y = 14

11y = 14 - 40

11y = - 26

y = {{{-26/11}}} = {{{-2}}}{{{5/11}}}.


Now substitute this value of y into equation (2) to get


2x + {{{(-26/11)}}} = 14  ====>

2x = 14 + {{{26/11}}} = {{{(14*11 + 26)/11}}} = {{{180/11}}} =====>  x = {{{90/11}}} = {{{8}}}{{{2/11}}}.


<U>Answer</U>.  x = {{{90/11}}} = {{{8}}}{{{2/11}}};  y = {{{-26/11}}} = {{{-2}}}{{{4/11}}}.
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After completing the solution, &nbsp;check on your own that the answer is valid.

For it, &nbsp;substitute the found values of x and y into the original equations.


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The method I used in the solution, &nbsp;is called the Substitution method.


See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF= http://www.algebra.com/algebra/homework/coordinate/lessons/Solution-of-the-lin-system-of-two-eqns-by-the-Subst-method.lesson>Solution of the linear system of two equations in two unknowns by the Substitution method</A> 

in this site.