Question 1130419


{{{-2x + 3y= 5}}}.....eq.1
{{{x = 2y- 4}}}......eq.2
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substitute {{{x}}} from eq.2 in eq.1

{{{-2(2y- 4) + 3y= 5}}}.....eq.1...solve for {{{y}}}

{{{-4y+ 8 + 3y= 5}}}

{{{-y+ 8 = 5}}}

{{{-5+ 8 = y}}}

{{{y=3}}}


find {{{x}}}:

{{{x = 2y- 4}}}......eq.2..substitute {{{y}}} 

{{{x = 2*3- 4}}}

{{{x = 6- 4}}}

{{{x = 2}}}



your solution:

({{{x}}}, {{{y}}}) =({{{2}}}, {{{3}}})