Question 1130387

P(1 or more sixes on roll of 6 dice) = 0.66510
P(2 or more sixes on roll of 12 dice) = 0.61867<br>

Person A is more likely to win. 

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Work:

6 dice
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P(1 or more sixes on roll of 6 dice) = 1 - P(0 sixes on roll of 6 dice)

= 1 - {{{ (5/6)^6 }}} = 1 - 0.33490 = 0.66510<br>


12 dice
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P(2 or more sixes on roll of 12 dice) = 1 - P(0 sixes) - P(1 six)

P(1 six) = (2C1)*{{{ (1/6)(5/6)^11 }}} = 0.269176
P(0 sixes) = {{{ (5/6)^12 }}} = 0.1121566

P(2 or more sixes) = 1 - 0.269176 - 0.1121566 = 0.61867