Question 1130338


{{{y = 3x-7}}}.....eq.1
{{{y= 5x-9}}}.....eq.2
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{{{y = 3x-7}}}.....eq.1..........substitute {{{y}}} from eq.2

{{{5x-9 = 3x-7}}}.....solve for {{{x}}}

{{{5x-3x = 9-7}}}

{{{2x = 2}}}

{{{x = 1}}}

go to {{{y= 5x-9}}}.....eq.2...substitute {{{1}}} for {{{x}}}


{{{y= 5*1-9}}}

{{{y= -4}}}


answer:

({{{x}}}, {{{y}}}) =({{{1}}}, {{{-4}}})