Question 102686
No! because with two unknowns (x and y) you couldn't do that.
All you need to do is to first to recognise that the x-intercept occurs at y = 0 and the y-intercept occurs at x = 0.
So, you can set y = 0 and solve for the corresponding value of x for the x-intercept. Let's do that first.
{{{x^2+y-36 = 0}}} Set y = 0 and solve for x.
{{{x^2+0-36 = 0}}} Add 36 to both sides.
{{{x^2 = 36}}} Take the square root of both sides.
{{{x = 6}}} or {{{x = -6}}} These are the x-intercepts.
Now set x = 0 and solve for y.
{{{x^2+y-36 =0}}} Set x = 0
{{{0+y-36 = 0}}} Add 36 to both sides.
{{{y = 36}}} This is the y-intercept.
Let's look at the graph of the equation to see this result.
{{{graph(400,600,-10,10,-5,40,-x^2+36)}}}