Question 1130254
If you will identify lowest or simplest denominator,  b(b+2), and multiply the left and right sides by this b(b+2), and simplify, you should obtain 
{{{b^2+3b-4=0}}}.


{{{(b+4)(b-1)=0}}}


One or both solutions are b=-4 or b=1.
Check each to see if either or both will work in original equation.