Question 1130150
x bags of 6% cement
5 bags of 18.8% cement
want 10% cement


{{{6x+(18.8)(5)=10(x+5)}}}

{{{(18.8)(5)-50=4x}}}

{{{x=(18.8*5-50)/4}}}

{{{x=11}}}



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USING THE PERCENTS AS DECIMAL FRACTIONS AND SETUP WITH RATIONAL EXPRESSION


{{{cement/concretemixture=fractionwanted}}}



{{{(0.06x+0.188*5)/(x+5)=0.10}}}

The algebra should be straightforward from here.