Question 1130102
Let {{{ b }}} = Brooke's OT hrs
Let {{{ d }}} = Derrick's OT hrs
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{{{ b = d + 9 }}}
{{{ b/d = 12/5 }}}
{{{ 5b = 12d }}}
and, by substitution:
{{{ 5*( d + 9 ) = 12d }}}
{{{ 5d + 45 = 12d }}}
{{{ 7d = 45 }}}
{{{ d = 6.4286 }}}
and
{{{ b = 6.4286 + 9 }}}
{{{ b = 15.4286 }}}
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Derrick worked 6.4 hrs OT
Brooke worked 15.4 hrs OT
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check:
{{{ b/d = 12/5 }}}
{{{ 15.4286/6.4286 = 12/5 }}}
{{{ 2.39999 = 2.4 }}}
OK