Question 1130096
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If the two are mutually exclusive, it means that P(E & F) = 0,


and then, using the general formula, you have


    P(E U F) = P(E) + P(F) - P(E & F) = P(E) + P(F) - 0 = P(E) + P(F).


So, your suggestion is correct.


The other, more visual way to see it is  to notice that <U>if the sets E and F are mutually exclusive</U>, then <U>the sets E and F are disjoint</U>.
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