Question 1130061

an  equation in slope intercept form:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept 


if line passes through the point ({{{6}}},{{{-3}}}) and have a slope of {{{-5/6}}}, we have

{{{-3=-(5/6)*6+b}}}.........solve for {{{b}}}

{{{-3=-(5/cross(6))*cross(6)+b}}}

{{{-3=-5+b}}}

{{{5-3=b}}}

{{{b=2}}}

and your line is: {{{y=-(5/6)x+2}}}



{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(6,-3,.12),locate(6,-3,p(6,-3)),
 graph( 600, 600, -10, 10, -10, 10, -(5/6)x+2)) }}}