Question 1130039
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The simplest way to solve the problem is to apply the Mechanical Energy conservation law.


The kinetic energy (when the body has its maximum speed - at the equilibrium position) is


    E = {{{(m*V^2)/2}}}.


The potential energy (when the body is maximally far from the equilibrium) is


    P = {{{(k*L^2)/2}}},


where "k" is the spring constant (given) and L is the maximum deviation from the equilibrium.


The conservation of energy law gives you  


    E = P,  which implies  {{{(m*V^2)/2}}} = {{{(k*L^2)/2}}},   or


    L = {{{sqrt((m*V^2)/k)}}}.


Substitute the given data to determine L:


    L = {{{sqrt((0.108*0.33^2)/28)}}} = 0.0205 m    (or 2.05 centimeters).


Maximal force is when the block is at the maximum deviation, and it is equal to


    F = k*L.


At the same time F = ma (Newton's second law), which gives you


    a = {{{(k*L)/m}}} = {{{(28*0.0205)/0.108}}} = 5.315 {{{m/s^2}}}.    <U>ANSWER</U>
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Solved.