Question 1130016
{{{ 6x + 3y = 12}}}

table:

{{{x}}}|{{{y}}}

{{{0}}}|{{{4}}}->{{{ 6*0 + 3y = 12}}}->{{{  3y = 12}}}->{{{ y = 4}}}

{{{2}}}|{{{0}}}->{{{ 6x + 3*0 = 12}}}->{{{ 6x = 12}}}->{{{ x = 2}}}

{{{4}}}|{{{-4}}}->{{{ 6*4 + 3y = 12}}}->{{{  3y = 12-24}}}->{{{ 3y = -12}}}->{{{ y = -4}}}

{{{1/2}}}|{{{3}}}->{{{ 6x + 3*3 = 12}}}->{{{ 6x = 12-9}}}->{{{ x = 3/6}}}->{{{ x = 1/2}}}


{{{drawing ( 600, 600, -10, 10, -10, 10,
circle(0,4,.12),circle(2,0,.12),circle(4,-4,.12),circle(1/2,3,.12),
locate(0,4,p(0,4)),locate(2,0.5,p(2,0)),locate(4,-4,p(4,-4)),locate(1/2,3,p(1/2,3)),
graph( 600, 600, -10, 10, -10, 10,-2x+4)) }}}