Question 102642
First solve for y:


{{{5 + 4y = 3x}}} Start with the given equation



{{{ 4y = 3x-5}}} Subtract 5 from both sides



{{{ cross((1/4)(4))y =(1/4)( 3x-5)}}} Multiply both sides by {{{1/4}}} to isolate y




{{{ y =(1/4)3x-(1/4)5)}}} Distribute



{{{ y =(3/4)3x-5/4)}}} Multiply. So now the equation is in slope-intercept form {{{y=mx+b}}} where the slope is {{{m=3/4}}} and the y-intercept is {{{b=-5/4}}}



Now let's find the equation of the line that is parallel to {{{ y =(3/4)3x-5/4)}}} and goes through (1,4)



*[invoke equation_parallel_or_perpendicular "parallel", "3/4", "-5/4", 1, 4]