Question 1129946
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Find the inverse of the​ one-to-one function.
f left parenthesis x right parenthesis equals 6 x plus 1
f Superscript negative 1 Baseline left parenthesis x right parenthesisequals 
nothing
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The given function should be represented  {{{f(x)=6x+1}}}.


Finding Inverse of f:

Let  {{{f^-1(x)}}} be the inverse of f(x).

{{{6*(f^-1(x))+1=x}}}

{{{6*(f^-1(x))=x-1}}}

{{{highlight(f^-1(x)=(x-1)/6)}}}