Question 1129943
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y varies directly as x and inversely as the square of z. 
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{{{y=kx/z^2}}}


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y equals 36 when x equals 27 and z equals 3. Find y when x equals 3 and z equals 12. 
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{{{k*27/3^2=36}}}


Solve for value of k and use it for the question.