Question 1129938
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Factor 3^1999 out of each term on the left....<br>
{{{3^2002 - 3^2001 + 3^2000 - 3^1999}}} =<br>
{{{(3^3)*3^1999 - (3^2)*3^1999 + 3*3^1999 - 1*3^1999}}} =<br>
{{{(27-9+3-1)*3^1999}}} =<br>
{{{20(3^1999)}}}<br>
ANSWER: n = 20