Question 1129918
Solve the following system of linear equations using elimination. (If there are infinitely many solutions, express x, y and z in terms of the parameter n. If there is no solution, enter NO SOLUTION.) 
x + y − 5z = 6
x +0y − 2z = 2
2x −y − z= 0
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Subtract 1st Eq from 2nd ; Subtract 2 times 1st Eq from 3rd to get:
x + y - 5z = 6
0x- y + 3z = -4
0x-3y + 9z = -12
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Add 3 times the 2nd Eq to the 3rd to get:
x + y - 5z = 6
0x -y + 3z = -4
0x 0y + 18z = -24
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Solve the 3rd Eq. for "z::
z = - 4/3
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Solve the 2nd Eq. for "y:
0x - y + 3(-4/3) = -4
-y - 4 = -4
y = 0
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Solve the 1st Eq. for "x"
x + 0 - 5(-4/3) = 6
x + 20/3 = 18/3
x = -2/3
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Cheers,
Stan H.
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