Question 102629




First convert the standard equation {{{x-2y=7}}} into slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 1, -2, 7, 2, 1]




Now let's find the equation of the line that is perpendicular to {{{y=(1/2)x-7/2}}} which goes through (0,-3)


*[invoke equation_parallel_or_perpendicular "perpendicular", "1/2", "-7/2", 0,-3]