Question 1129832
For both the sin and cos, the range is -1 to +1
So, the range of x is {{{ pi }}} to {{{ 2pi }}}
( the right side cannot be greater than 1 )
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{{{ x = pi }}}
{{{ cos( pi ) = sin( pi ) + 1 }}}
{{{ -1 = 0 + 1 }}} not true
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{{{ x = 3*(pi/2) }}}
{{{ cos( 3*(pi/2) ) = sin( 3*(pi/2) ) + 1 }}}
{{{ 0 = -1 + 1 }}} true
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{{{ x = 2pi }}}
{{{ cos( 2pi ) = sin( 2pi ) + 1 }}}
{{{ 1 = 0 + 1 }}} true
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{{{ x = 3*(pi/2) }}} and
{{{ x = 2pi }}}
are the solutions