Question 1129771
let the consecutive integers be:
{{{ n }}} and {{{ n+ 1 }}}
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{{{ n*( n + 1 ) = 3*( n + n + 1 ) - 7 }}}
{{{ n^2 + n = 6n + 3 - 7 }}}
{{{ n^2 - 5n + 4 = 0 }}}
{{{ ( n - 4 )*( n - 1 ) = 0 }}}
{{{ n = 4 }}}
{{{ n = 1 }}}
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{{{ n - 4 }}}
{{{ n + 1 = 5 }}}
{{{ n*( n+ 1 ) = 3*( n + n + 1 ) - 7 }}}
{{{ 4*5 = 3*( 4 + 5 ) - 7 }}}
{{{ 20 = 27 - 7 }}}
{{{ 20 = 20 }}}
OK
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{{{ n = 1 }}}
{{{ n + 1 = 2 }}}
{{{ n*( n+1 ) = 3*( n + n + 1 ) - 7 }}}
{{{ 1*2 = 3*( 1 + 2 ) - 7 }}}
{{{ 2 = 9 - 7 }}}
{{{ 2 = 2 }}}
OK
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There are 2 answers:
1 and 2
and also:
4 and 5