Question 1129641
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<pre>
Use the Hagen-Poiseuille equation


    Q = {{{(pi*R^4*DELTA(P))/(8*mu*L)}}}


in standard fluid-kinetics notation

  &#916;P is the pressure difference between the two ends,
  L is the length of pipe,
  &#956; is the dynamic viscosity,
  Q is the volumetric flow rate,
  R is the pipe radius.


In your case  Q = {{{(3.14*0.00134^4*420)/(8*2.1*10^(-3)*0.05)}}} = {{{5.06*10^(-6)}}} m^3/s = 5.06 cm^3/s.


<U>Answer</U>.  5 cubic centimeters per second, approximately.
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On the Hagen-Poiseuille equation, &nbsp;see these links


http://fluid.itcmp.pwr.wroc.pl/~znmp/dydaktyka/fundam_FM/Lecture13.pdf


https://en.wikipedia.org/wiki/Hagen%E2%80%93Poiseuille_equation