Question 1129706

 Convert the equation {{{2x-y+2=0}}} to polar form:

Substitute:

{{{x=r*cos(theta)}}}
{{{y=r*sin(theta)}}}


{{{2r*cos(theta)-r*sin(theta)+2=0}}}-> polar form


now solve the resulting equation for {{{r}}}


{{{(2cos(theta)-sin(theta))r=-2}}}


{{{r=-2/(2cos(theta)-sin(theta))}}}