Question 102441
{{{(a^3+27)/(4a^2-36)}}}
:
The numerator can be factored as the "Sum of Cubes"
The denominator can be factored as the "difference of squares"
{{{((a + 3)(a^2 - 3a + 9))/((2a - 6)(2a + 6))}}}
:
Factor out the 2:
{{{((a + 3)(a^2 - 3a + 9))/(2(a - 3)*2(a + 3))}}}
:
Cancel out (a+3)'s
{{{((a^2 - 3a + 9))/(4(a - 3))}}}