Question 1129713


{{{V[1] = (1/3)pi*h^2(3r-h)}}}

if {{{2m}}} is diameter -> then radius is {{{r=1m}}}, {{{V=1396L}}}->{{{1396L= 1.396000m^3}}}

{{{V[1]= (1/3)pi*1.75^2(3*1-1.75)}}}

{{{V[1] = 4.0088m^3}}}=>.......{{{4.0088m^3=4008.8L }}}

{{{V[1]-V =4008.8L - 1396L}}}}

{{{V[1]-V =2612.8L}}}

 {{{V[1]-V =2613L}}}