Question 1129692
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There are many different ways to solve this problem using formal algebra.  All of them result in a quadratic equation that needs to be factored to solve the problem.<br>
One response you have received shows the work up to "c(c-11)=180" and then gives the (wrong) answers without showing how the equation was solved.<br>
A different formal algebraic solution I tried ends up with an uglier quadratic equation which is even harder to solve by factoring.<br>
But if a formal algebraic solution is not required, the original problem can be solved with logical trial and error, requiring mathematics that is far simpler than any algebraic solution.<br>
The original problem requires you to find two whole numbers whose product is 60, with one of the numbers being 11 more than 3 times the other.<br>
There aren't a lot of pairs of whole numbers whose product is 60; and the requirement that one of them be MUCH larger than the other leaves only a couple of possibilities to try: 2 and 30, or 3 and 20.<br>
The pair 3 and 20 satisfies the second requirement; it is the answer.