Question 1129688


{{{(2 / (y^2+y) - 2 / (xy+x) )/(1 / (xy+x) - 1 / (y^2+y) )}}}


={{{(2 / y(y+1) - 2 / x(y+1) )/(1 / x(y+1) - 1 / y(y+1) )}}}



={{{(2x(y+1)  / (xy(y+1)^2) - 2y(y+1) / (xy(y+1)^2) )/(y(y+1) / (xy(y+1)^2)  - x(y+1) / (xy(y+1)^2) )}}}




={{{((2x(y+1) - 2y(y+1))/cross(xy(y+1)^2))/((y(y+1) - x(y+1)) / cross((xy(y+1)^2)))}}}



={{{(2x(y+1) - 2y(y+1) )/(y(y+1) - x(y+1))}}}


={{{((2x - 2y)cross((y+1) ))/((y - x)cross((y+1)))}}}


={{{(2x - 2y)/(y - x)}}}


={{{-2cross((y - x))/cross((y - x))}}}


={{{-2}}}