Question 102589
{{{ 3y=3x+9}}} Start with the given equation



{{{ cross(3/3)y=(3x+9)/3}}} Divide both sides by 3 to isolate y



{{{ y=(3/3)x+9/3}}} Break up the fraction



{{{ y=1*x+3}}} Reduce. So the equation is now in slope-intercept form {{{y=mx+b}}} where the slope is {{{m=1}}} and the y-intercept is {{{b=3}}}