Question 1129647
Let {{{ q }}} = number of quarters
Let {{{ n }}} = number of nickels
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(1) {{{ n + q = 16 }}}
(2) {{{ 5n + 25q = 260 }}}
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(2) {{{ n + 5q = 52 }}}
Subtract (1) from (2)
{{{ n + 5q = 52 }}}
{{{ -n - q = -16 }}}
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{{{ 4q = 36 }}}
{{{ q = 9 }}}
and
(1) {{{ n + 9 = 16 }}}
(1) {{{ n = 7 }}}
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7 nickels
9 quarters
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check:
{{{ 5n + 25q = 260 }}}
{{{ 5*7 + 25*9 = 260 }}}
{{{ 35 + 225 = 260 }}}
{{{ 260 = 260 }}}
OK